WebSubtract: 2 (ab + bc + ca) from -ab - bc - ca. Solution We have, -ab - bc - ca - 2 (ab + bc + ca) = - ab - bc - ca - 2ab - 2bc - 2ca On combining the like terms, = - ab - 2ab - bc - 2bc - ca - … WebSubtract: 2(ab+bc+ca)from −ab−bc−ca. Medium. Open in App. Solution. Verified by Toppr. (−ab−bc−ca)−{2(ab+bc+ca)} =−ab−bc−ca−2ab−2bc−2ca. =−3ab−3bc−3ca.

Solve b^2+c^2-a^2=bc Microsoft Math Solver

WebSubtract ab - bc - ca from - ab + bc + ca. Solution: Given, the expressions are ab - bc - ca and - ab + bc + ca. We have to subtract the expressions. On subtracting the expressions, = - ab … Web5 Jan 2024 · Answer: 2ab-2bc-2ca Step-by-step explanation: ab-bc-ca- (-ab+bc+ca) =ab-bc-ca+ab-bc-ca =2ab-2bc-2ca Advertisement hemaupreti297 Step-by-step explanation: ab - … rbi 21 switch review

How to prove the inequality $a/(b+c)+b/(a+c)+c/(a+b) \\ge 3/2$

Webab + bc + ca = 100 Using the a 2 + b 2 + c 2 formula, a 2 + b 2 + c 2 = (a + b + c) 2 - 2 (ab + bc + ca) a 2 + b 2 + c 2 = (20) 2 - 2 (100) = 400 - 200 = 200 Answer: a 2 + b 2 + c 2 = 200. FAQs on a 2 + b 2 + c 2 Formulas What Is the Expansion of a 2 + b 2 + c 2 Formula? a 2 + b 2 + c 2 formula is read as a square plus b square plus c square. WebSubtract -a² - ab from b² + ab Solution: Given, the expressions are -a² - ab and b² + ab. We have to subtract the expressions On subtracting the expressions, = b² + ab - (-a² - ab) By combining the like terms, = b² + ab + a² + ab By distributive property, = b² + a² + (1 + 1)ab = a² + b² + (2)ab = a² + b² + 2ab WebSelina solutions for Class 6 Mathematics chapter 19 (Fundamental Operations (Related to Algebraic Expressions)) include all questions with solution and detail explanation. This … rbi 5th cohort